Code Solution

Input Format

• The first line of input contains an integer T$T$, denoting the number of test cases. The description of T$T$ test cases follows.
• The first and only line of each test case contains three space-separated integers X,Y$X,Y$ and Z$Z$ — the number of stocks, the price they were bought at, and the price they can be sold at, respectively.

Output Format

For each test case print on a new line a single integer — Chef's profit after selling all the stocks he has.

Constraints

• 1≤T≤100$1\le T\le 100$
• 1≤X,Y≤104$1\le X,Y\le {10}^4$
• Y≤Z≤104$Y\le Z\le {10}^4$

Sample Input 1 

3
2 5 20
3 1 2
4 5 6

Sample Output 1 

30
3
4

Explanation

Test Case 1: Chef bought X=2$X=2$ stocks for Y=5$Y=5$ each, making the total amount spent by Chef =2⋅5=10$=2\cdot 5=10$.

Chef can sell this stock today for Z=20$Z=20$, making the total amount received by Chef =2⋅20=40$=2\cdot 20=40$.

The total profit is then the amount received minus the amount spent, which equals 40−10=30$40-10=30$.

Test Case 2: Chef bought X=3$X=3$ stocks for Y=1$Y=1$ each, making the total amount spent by Chef =3⋅1=3$=3\cdot 1=3$.

Chef can sell this stock today for Z=2$Z=2$, making the total amount received by Chef =3⋅2=6$=3\cdot 2=6$.

The total profit is then the amount received minus the amount spent, which equals 6−3=3$6-3=3$.

Test Case 3: Chef bought X=4$X=4$ stocks for Y=5$Y=5$ each, making the total amount spent by Chef =4⋅5=20$=4\cdot 5=20$.

Chef can sell this stock today for Z=6$Z=6$, making the total amount received by Chef =4⋅6=24$=4\cdot 6=24$.

The total profit is then the amount received minus the amount spent, which equals 24−20=4

Solution

#include <iostream>

using namespace std;

int main()

{

    int t;

    cin>>t;

    while(t--){

        int x,y,z;

        cin>>x>>y>>z;

        int a=x*y;

        int b=x*z;

        cout<<b-a<<endl;

    }

    return 0;

}

Solution